Question

a man holds a ball of mass (1/2) kg in his hand . he throws it vertically upwards . During this process he moves up by 40 cm and the ball. leaves his hand with an upward velocity of 4m/s . The constant force with which tge man pushes tge ball is​

Answer 1

Answer:

Explanation:

F=ma

F=MV/t -(1)

We have all the values except t,

So, s =ut (constant force, a=O)

0.04=4×t

T=4/400=1/100

Now substitute it in (1)

F=1/2×4/1/100= 200N

Answer 2

MARK ME AS BRAINLIEST PLEASE