Question

A man holds a spherical shaving mirror of radius of curvature 60 cm, and focal length 30 cm, at a distance of 15 cm, from his nose. Find the position of image, and calculate the magnification.

Answer 1

The position of the image is 30cm and the magnification is 2. So, the image formed is magnified, virtual and erect.

Explanation:

A Shaving mirror is always a concave mirror.

f = -30cm

u = -15cm

As per the formula of mirror,

 $\frac{1}{f} = \frac{1}{v} +\frac{1}{u}$

$\frac{1}{-30} = \frac{1}{v} +\frac{1}{-15}$

$\frac{-1}{30} +\frac{1}{15} =\frac{1}{v}$

v = 30cm.

So, the position of the image is 30cm.

According to the formula of magnification,  

$\frac{-v}{u} = \frac{-(30)}{-15} = 2$

Thus, the image is magnified, virtual and erect.

You can get all the answers of Chapter 4 in the link below:

https://brainly.in/question/14963178

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Answer 2

Answer:

Given:- R=60cm , f=-30cm, U=-15cm

1/v+1/u =1/f

1/v + 1/-15 =1/-30

1/v=1/15+1/-30

1/v=2-1/30

1/v=1/30

V=30

M=-v/u

M=-30/-15

M=+2