Question

A man holds four balls 180 m above the ground and
drops them at regular intervals of time so that when
the first ball hits ground, the fourth ball is just leaving
his hand. At this time, the second and third balls from
the ground are at the positions...
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Answer 1

Answer:

MARK IT AS BRAINLIEST

Explanation:

​Time taken by first ball h reach the ground

=2Hg−−−√=2×18010−−−−−√=6sec

time interval between two balls in 2 seconds

H1=12g(4)2=80m

H1=12g(2)2=20m

Height from ground are 180−80=100m

180−20=160m

HENCE IT IS A CORRECT ANSWER