A man in a balloon rising vertically with an acceleration of 4.9m/s release a ball 2 second after the balloon is let go from the ground. The greatest height above the ground reached by the ball is (g=9.8m/s^2)
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Answer:
14.7 +9.8
Explanation:
after 2 sec balloon will reach height
4.9+9.8=14.7
now the ball gets intial velocity same as balloon
u=9.8 m/s
which will go 9.8 meter more up as g=9.8
so
H max= 14.7+9.8
I did it logically u can do it by kinematic equation
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