A man in a balloon, throws a stone downwards with a speed of 5m/s with respect to the balloon. The balloon is moving upwards with a constant acceleration of 5m/s 2 . Then what is the velocity of the stone relative to the man after 2 seconds?
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hi i have a solution for you
The answer would be 19 cm / sec in downward direction
Solution will be as follows:
Velocity of a / b = 5 cm / sec Relative acceleration = 0i - ( g + 2 )
Relative velocity after 2 sec final = v ( r ) - a ( r ) t
= 5 - 12 * 2
= - 19 m / sec
The answer would be 19 cm / sec in downward direction
Solution will be as follows:
Velocity of a / b = 5 cm / sec Relative acceleration = 0i - ( g + 2 )
Relative velocity after 2 sec final = v ( r ) - a ( r ) t
= 5 - 12 * 2
= - 19 m / sec
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