Question

A man in ballon rising verticallywith acceleration of 4.9 releases a ball2sec after the ballon is let go from ground the greatest height above the ground reaches by ball is

Answer 1

Answer:

a=4.9㎨

Initial velocity =0

Velocity of balloon and ball after 2 sec

v=u+at=9.8㎧

Height at this point

h=

2

1

at

2

=0.5×4.9×4

=9.8m

The ball will attain further height =s

2

1

mv

2

=mgs

s=

2g

v

2

=4.9m

Greatest height that can be achieved

H=h+s=9.8+4.9=14.7m