Physics, asked by Hridayboro, 1 month ago

A man increases its speed from 5km/hrs to 2km/hrs in 4sec. Find the distance travelled?​

Answers

Answered by anthonypaulvilly
0

Answer:

    s = 3.89 m

Explanation:

u = 5km/hr = 5× 5/18 m/s

v = 2km/hr = 2× 5/18 m/s

t = 4 sec

v = u + at

a = v - u / t

  = 2×5/18 - 5×5/18 / 4

  = 5/18 (2 - 5) / 4

  = 5 × -3 / 4×18

  = -5 / 4 × 6

a  = -5/24 ms⁻²

s = ut + at² / 2

s = ( 4 ×5 × 5/18 ) + (-5 / 24 × 4 × 4 /2)

s = (50 / 9) - (5 / 3)

s = 50 / 9 - 15 / 9

s = 35 / 9 m

s = 3.89 m

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