A man increases its speed from 5km/hrs to 2km/hrs in 4sec. Find the distance travelled?
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Answer:
s = 3.89 m
Explanation:
u = 5km/hr = 5× 5/18 m/s
v = 2km/hr = 2× 5/18 m/s
t = 4 sec
v = u + at
a = v - u / t
= 2×5/18 - 5×5/18 / 4
= 5/18 (2 - 5) / 4
= 5 × -3 / 4×18
= -5 / 4 × 6
a = -5/24 ms⁻²
s = ut + at² / 2
s = ( 4 ×5 × 5/18 ) + (-5 / 24 × 4 × 4 /2)
s = (50 / 9) - (5 / 3)
s = 50 / 9 - 15 / 9
s = 35 / 9 m
s = 3.89 m
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