Question

A man inside a lift moving up with
g/2 acceleration has apparent weight W¹. The same man
inside the lift moving down with an acceleration of g/2 has an apparent weight of W².Then the value of W¹/W²​

Answer 1

Answer:

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Answer 2

Answer:

Solution :

(a) W1=m(g+a),W2=m(g−a)

W1+W2=2mg⇒W1+W2=2W(∵W=mg)

⇒W1+W22=W

(b) W1W2=m(g+a)m(g−a)=g+ag−a

ga=W1+W2W1+W2⇒a=g(W1−W2W1+W2) .