a man invest 10000 for 3 years at a certain rate of interest compounded annually at the end of one year it amounts to 11200 calculate the rate of interest per annum second interest accurate in the second year third the amount at the end of the third year
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Answer:
we have P= 10000 R= ? T= 3 Years
Step-by-step explanation:
we have SI = A-P= 11200-10000= 1200
R = SI *100/P×T i.e 1200×100/10000×3= 4%
P=10000 R= 4% T=3 years
SI = PRT/100= 11200×4×3/100= 1344
A=P+ SI= 11200+1344 =12544
P =12544 R=4% T= 3 years
SI=PRT/100 = 12544×4×3/100=1505·28.
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