Question

A man invested 10000Rs and split into two schemes ,at annual interest 8% & 9%.afye one year he got 875rs as interest from both.how much did he invest in each?

Answer 1

1. Let x  be the amount invested at rate of 8%.Hence 10000-x will be the amount invested at 9%
2. we know SI=ptr/100=x*1*8/100
3. and other SI=(10000-x)*1*9/100
4. he got 875rs as interest  on both investments i.e,
5. (8x/100)+((10000-x)*9/100) =875
6. On solving this we get x=2500 i.e,2500 is invested at rate of 8% and 10000-x=7500 is the amount invesred at rate os 9%