Question

A man invested ₹ 5000 at a simple interest of 10% annually. What is the total amount he will get after 2 years ​

Answer 1

Answer:

Here,  

Principal for the first year P  

1

​  

=5,000 Rs.,  

Amount at the end of the year A  

1

​  

=5,150 Rs.

I=A  

1

​  

−P  

1

​  

=150 Rs.

Rate of interest =  

P×T

100×I

​  

=  

5000×1

100×150

​  

=3

Now, For 2nd Year

P=P  

1

​  

+I=5,000+150=5150

Interest for the second year =  

100

P×T×R

​  

 

                                               =  

100

5150×1×3

​  

 

                                               =154.5

Hence, the answer is Rs. 154.5

Step-by-step explanation:

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Answer 2

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GIVEN :-

Principal = Rs. 5000,

Rate% = 10 %

Time = 2 years.

TO FIND :-

Find the total amount he will get after 2 years.

SOLUTION :-

Principal = Rs. 5000,

Rate% = 10 %

Time = 2 years.

SI for 2 years

= 5000 × 2 × 10 / 100

= 1000

NOTE :-

When interest is compounded semi annually.

New Cost%

= 10/2 

= 5 %

Time

= 2 × 22 × 2

= 4 years

Effective Rate % of for 4 years

= 21.55 %

Required CI

=5000 × 21.55 / 100

= Rs. 1077.50

Required Amount.

= Rs. ( 1077.50 - 1000 )

= Rs. 77.50