A man invested 6,000 in three parts at simple interest—first part at 3% p.a. for 4 years.
second part at 4% p.a. for 5 years and the third part at 5% p.a. for 3 years. If the interes
received on each part is equal, find that part which was invested at 5% p.a.
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Answers
Answered by
4
Step-by-step explanation:
Let the two parts be x ans 6000−x
Simple interest = 100
principle×rate×time
⇒ 100x(6)(2)
= 100/(6000−x)(8)(3)
⇒x=12000−2x
⇒3x=12000
⇒x=4000
To parts are Rs.4000, 2000
Answered by
2
Answer:
Simple interest =100
Principal× Rate ×Time
=>100×(6)(2)
=>100/(6000-x)(8)(3)
=>X=12000-2x
=>3x=12000
=>X=4000
To part are ₹ 4000,2000
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