Math, asked by rashpratham, 5 months ago

A man invested 6,000 in three parts at simple interest—first part at 3% p.a. for 4 years.
second part at 4% p.a. for 5 years and the third part at 5% p.a. for 3 years. If the interes
received on each part is equal, find that part which was invested at 5% p.a.

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Answers

Answered by vaibhav589sanaya
4

Step-by-step explanation:

Let the two parts be x ans 6000−x

Simple interest = 100

principle×rate×time

⇒ 100x(6)(2)

= 100/(6000−x)(8)(3)

⇒x=12000−2x

⇒3x=12000

⇒x=4000

To parts are Rs.4000, 2000

Answered by deepamishra521
2

Answer:

Simple interest =100

Principal× Rate ×Time

=>100×(6)(2)

=>100/(6000-x)(8)(3)

=>X=12000-2x

=>3x=12000

=>X=4000

To part are ₹ 4000,2000

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