A man invested 6000 and get 1200 after 2 year find the rate of interest (SI)
Answers
Answered by
0
Answer:
Solution
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Correct option is A)
P=6000 per month , R=5%
After 1 year
Interest=
100
PRT
=
100
6000×5×1
=300
New principle will be 6000+300=6300 but Rs 1200 was repaid
⟹P
′
=6300−1200=5100
After 2 years
Interest=
100
P
′
RT
=
100
5100×5×1
=255
Principle for 3
rd
year =5100+255=5355 but again Rs 1200 was repaid
∴ Outstanding =5355−1200
=4155
Step-by-step explanation:
Answered by
0
Answer:
10%
Step-by-step explanation:
SI = P×R×T/100
1200 = 6000×R×2/100
1200 = 60×R×2
1200 = 120×R
R = 1200/120
R= 10%
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