A man invested a certain amount of money at 5% simple interest and gained 300 dollar in 6 years. how much money did he invest?
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Answers
Answered by
0
Answer: p=rs5000
Step-by-step explanation:
According to the given question
Intersect per year =10,000×5 %
=10,000×1005
=500
Now,
Amount in Ist years =10,000
Amount in 2nd year =10,000+intersect
=10,000+500=10,500
Amount in 3rd year =10,500+Intersect
=10,500+500=11,000
Then our series becomes
10,000,10,500,11000........
This is an AP
where a=10,000
d=10,500−10,000=500
time (n)=15 year
Then,
Amount in 15th year =a+(n−1)d
=10,000+(15−1)×500
=10,000+14×500
10,000+7000
17,000
Thus amount in 15th year in Rs.17,000
Amount of per 20 year =an
=a+(n−1)d
10,000+(21−1)×500
10,000+10,000
20,000
Thus, the amount in 20th years is
Rs.⇒20,000/−
Hence, this is the answer.
Answered by
1
Step-by-step explanation:
300 = P * 0.05 * 6 =>
300 = 0.3P =>
300 / 0.3 = P =>
1000 = P
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