Math, asked by justastudent24, 6 months ago

A man invested a sum of money in three companies A, B and C. He invested 32% of his money in company A, 12% in company B and the rest in company C. If his investment in company C was 2,10,000, then find:
a. the total money invested by the man
b. investment in company A
c. investment in company B


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Answers

Answered by aditya3409
28

Given

company A invested 32 %

company B invested 12%

company C invested 2,10,000

a) the total money invested by the man

100-(32%+12%)=56%

56/100 x = 2,10,000

0.56x = 2,10,000

x = 2,10,000/0.56

x = 21000000/56

x = 3,75,000

b) investment in company A

A = 32%

A = 32/100x 3,75,000

A = 1,20,000

c) investment in in company B

B = 12%

B = 12/100x 3,75,000

B = 45,000

Answered by propanti13
11

Answer:

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Step-by-step explanation:

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