A man invested a sum of money in three companies A, B and C. He invested 32% of his money in company A, 12% in company B and the rest in company C. If his investment in company C was 2,10,000, then find:
a. the total money invested by the man
b. investment in company A
c. investment in company B
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Answers
Answered by
28
Given
company A invested 32 %
company B invested 12%
company C invested 2,10,000
a) the total money invested by the man
100-(32%+12%)=56%
56/100 x = 2,10,000
0.56x = 2,10,000
x = 2,10,000/0.56
x = 21000000/56
x = 3,75,000
b) investment in company A
A = 32%
A = 32/100x 3,75,000
A = 1,20,000
c) investment in in company B
B = 12%
B = 12/100x 3,75,000
B = 45,000
Answered by
11
Answer:
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