Math, asked by Navya5756, 3 months ago

A man invested Rs. 16000 at compound interest for 3 years, interest compounded annually. If he got Rs. 18522 at the end of 3 years, then the rate of interest is ? ​

Answers

Answered by nilesh102
5

Given data : A man invested Rs. 16000 at compound interest for 3 years, interest compounded annually. If he got Rs. 18522 at the end of 3 years.

Now, according to given :

⟹ P = Principal (initial value) = Rs 16000

⟹ A = Amount (final/future value) = Rs 18522

⟹ n = Time (number of times conpounded in one "t") = let, 100

⟹ t = time = 3 years

Let the rate of interest be 'r'.

⟹ Rate of interest = r = ?

Now, by formula :

⟹ A = P * {1 + r/n}^(t)

⟹ 18522 = 16000 * {1 + r/100}³

⟹ 18522/16000 = {1 + r/100}³

⟹ 9261/8000 = {1 + r/100}³

⟹ ³√(9261/8000) = 1 + r/100

⟹ 21/20 = 1 + r/100

⟹ 21/20 - 1 = r/100

⟹ (21 - 20)/20 = r/100

⟹ 1/20 = r/100

⟹ 1/20 * 100 = r i.e.

⟹ r = 100/20

⟹ r = 5 %

Answer : Hence, the rate of interest is 5 %.

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Answered by kanchanabandi2
4

Answer:

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