a man invested rupees 10000 in a bank for 3 by 2 years at the interest rate of 15 by 2% per annum compounded annually find the amount he received at the end of the period
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Step-by-step explanation:
(P) Principal = Rs.10000
(t) Time period = 3/2 years or 1 and 1/2 years
(r) Rate = 15% per annum (compounded annually)
(n) Number of times compounded in a time period
(A) Amount = P(1+r/(100*n))^n*t
Therefore, Amount = 10000(1+15/100)(1+15/200)
= 10000(115/100)(215/200)
= Rs.12362.50
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compound interest = 11,145.84
interest earned = 1,145.84
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