Question

A man invests 10400 in 6% shares at 104 and 11440 in 10.4% shares at 143. How much income would he get in all?​

Answer 1

Answer:The man's total income is 1813.76

Step-by-step explanation:

Given

Investment of Rs 10400 in 6% shares=Rs 104

investment of Rs 11440 in 10.4% shares=Rs 143

From the given above statement

We have

Income on Rs 104

= 6% n Rs 10400

= 6 x 104

=624

Income on Rs 104 =Rs 624

Income on Rs 143

= 10.4% n Rs 11440

= 11897.6/10

=1189.76

Income on Rs 143 =Rs 1189.76

Therefore total income = [Income on Rs 104 +Income on Rs 143]

=Rs 624 + Rs 1189.76

=Rs 1813.76

Hence a man gets a total income of Rs 1813.76

Answer 2

Given:

Income of Rs. 104 = 6% of Rs. 10400.

Income of Rs. 143 = 10.4% of Rs. 11440.

To Find:

Income would get in all.

Solution:

Case 1: Income of Rs. 104 = 6% of Rs. 10400.

$\dashrightarrow\: \sf\Large \frac{6}{100}$ × 10400

•°• Income on Re 1 = $\sf\Large\ \frac{6×10400}{100×104}$

$\dashrightarrow\: \underline{\boxed{\bf{\purple{Rs. 6}}}}$

Case 2: Income of Rs. 143 = 10.4% of Rs. 11440.

$\dashrightarrow\: \sf\Large\ \frac{104}{10×100}$ ×11440

$\dashrightarrow\: \sf\Large\ \frac{104×1144}{100}$

•°• Income on Re 1 = $\sf\Large\ \frac{104×1144}{100×143}$ = $\sf\Large\ \frac{8×104}{100}$

$\dashrightarrow\: \sf\Large\ \frac{832}{100}$

$\dashrightarrow\: \underline{\boxed{\bf{\purple{Rs.8.32 }}}}$

•°• Total income earned by man = Rs. 6 + Rs. 8.32

$\dashrightarrow\: \underline{\boxed{\bf{\red{Rs.14.32 }}}}$