A man invests 1200 for two years at compound interest. After one year the money
amounts to 1275. Find the interest for the second year correct to the nearest rupee.
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Sum=Rs.1200
Amount after one year=Rs.1275
interest for one year=1275−1200=Rs.75
C.I for one year=S.I for one year
interest=
100
PRT
⇒75=
100
1200×R×1
⇒R=
1200×1
75×100
⇒R=6
4
1
%
For second year
Sum=Rs.1275
interest=
100×4
1275×25×1
=79.68=Rs8
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