Math, asked by AkshatKumarShaw, 1 month ago

A man invests 212000 for 3 years at 10% per annum compound interest in a bank. Find: a) The compound interest for second year. b) Principal for the third year.​

Answers

Answered by nayanpogade
0

Answer:

880

Compound interest for the second year will be the simple interest gained in the second year, with the amount after first year being the principal for the second year.

For the first year

P=Rs8,000

N=1year

R=10 %

We have S.I.=

100

PNR

=

100

8,000×1×10

=Rs800

And Amount at the end of first year P+S.I.=Rs8,000+Rs800=Rs8,800

Now, for the second year

P=Rs8,800

N=1year

R=10 %

We have S.I.=

100

PNR

=

100

8,800×1×10

=Rs880

Thus, Compound interest for the second year =Rs880

Answered by atharvavermaRDJ
0

Answer:

Yo

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