Math, asked by connectaarsh, 10 months ago

A man invests 5,600 at 14% per annum compound interest for 2 years. Calculate : (i) the interest for the first year. (ii) the amount at the end of the first year. (iii) the interest for the second year, correct to the nearest rupee.​

Answers

Answered by anthonyruben06
2

Answer:

100600

Step-by-step explanation:

rasy dude hope helps you

Answered by shanvisharma
17

Answer:For the first year:

P= Rs. 5,600, N=1 year and R=14%

We have S.I. =

100

PNR

=

100

5,600×1×14

= Rs. 784

And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384

Now, for the second year :

P= Rs. 6,384, N=1 year and R=14%

We have S.I.=

100

PNR

=

100

6,384×1×14

= Rs. 893.76

To the nearest rupee, it is Rs. 894.

HOPE IT HELPED U DUDE.✌️✌️

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