a man invests ₹7200 in 13% shares of face value ₹100 at ₹120 and ₹1800 in 6% shares of face value ₹100 at ₹90. find the rate on his investment
Answers
Answer:
Face value of each share = Rs 100
Market value of each share = Rs 112
Money invested by man = Rs 10080
& Rate of dividend = 6%
∴ Number of shares bought by him = Money invested/Market value of one share
= 10080/112 = 90
Now, annual income on one share = 6100 × 100 = Rs 6
Therefore, annual income on 90 shares = Rs (90 × 6) = Rs 540
In 2nd case:
Money received by him on selling one share = Rs 96
then money received by him on selling 90 shares = Rs (90 × 96) = Rs 8640
Hence, money invested by him in 2nd case = Rs 8640
Now, Face value of each new share = Rs 10
Market value of each new share = Rs 8
& Rate of dividend = 10%
Hence, number of shares he bought in 2nd case = 86408 = 1080
Now, income on one share = 10 × 10100 = Re 1
then income of 1080 shares = Rs (1080 × 1) = Rs 1080
Hence, the change in his annual income = Rs 1080 − Rs 540 = Rs 540
Face value of each share = Rs 100
Market value of each share = Rs 112
Money invested by man = Rs 10080
& Rate of dividend = 6%
∴ Number of shares bought by him = Money invested/Market value of one share
= 10080/112 = 90
Now, annual income on one share = 6100 × 100 = Rs 6
Therefore, annual income on 90 shares = Rs (90 × 6) = Rs 540
In 2nd case:
Money received by him on selling one share = Rs 96
then money received by him on selling 90 shares = Rs (90 × 96) = Rs 8640
Hence, money invested by him in 2nd case = Rs 8640
Now, Face value of each new share = Rs 10
Market value of each new share = Rs 8
& Rate of dividend = 10%
Hence, number of shares he bought in 2nd case = 86408 = 1080
Now, income on one share = 10 × 10100 = Re 1
then income of 1080 shares = Rs (1080 × 1) = Rs 1080
Hence, the change in his annual income = Rs 1080 − Rs 540 = Rs 540
I hope it's helpful