A man invests a certain sum of money at 6% p.a. simple interest and another sum at 7% p.a. simple interest. His income from interest after 2 years was Rs.354. One fourth of the first sum is equal to one fifth of the second sum. Find sum invested in each.
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Let assume that
- Sum invested at 6% per annum be Rs x
and
- Sum invested at 7 % per annum be Rs y.
According to statement
☆ One fourth of the first sum is equal to one fifth of the second sum.
We know,
Simple Interest on a certain sum of money P invested at the rate of R % per annum for T years is
Now,
It is given that,
☆ Rs x is invested for 2 years at the eate of 6 % per annum simple interest,
Also,
☆ Rs y is invested for 2 years at the rate 7 % per annum simple interest,
According to statement
☆ His income from interest after 2 years is Rs 354
☆ On substituting the value of y in equation (1), we get
Hence,
- Sum invested at 6% per annum be Rs 1200
and
- Sum invested at 7 % per annum be Rs 1500
Basic Concept Used :-
Basic Concept Used :- Writing Systems of Linear Equation from Word Problem.
1. Understand the problem.
- Understand all the words used in stating the problem.
- Understand what you are asked to find.
2. Translate the problem to an equation.
- Assign a variable (or variables) to represent the unknown.
- Clearly state what the variable represents.
3. Carry out the plan and solve the problem.
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