Question

A man invests a part of rs 10000 at 5% and the remainder at 6%. the 5% investment yields annually rs 76.50 more than the 6% investment. the amount invested at 6% is

Answer 1

(x*5/100)-((10000-x)*6/100)=76.5
1/100(5X-60000+6X=76.5
11X-60000=7650
11X=67650
X=6150=amount invested at 5%

Answer 2

Let the part investedon 5% = Rs.x

Remaining part = Rs.(10,000 - x)

According to the question,

x×5100−(10000−x)×6100=76.50x×5100−(10000−x)×6100=76.50

5x100−600+6x100=76.505x100−600+6x100=76.50

11x100=76.50+60011x100=76.50+600

11x100=676.5011x100=676.50

⇒⇒x=6765011x=6765011

⇒x=6150⇒x=6150

Amount invested on 6% = (10,000 - 6150) = Rs.3850