Question

A man invests an amount of Rs. 15860 in the names of his three sons A, B and C in such a way that they get the same interest after 2, 3 and 4 years respectively. If the rate of simple interest is 5%, then the ratio of the amounts invested among A, B and C will be

Answer 1

Solution

Let the amount invested be x, y and z respectively 

Then 

(x*2*5)/100 = (y*3*5)/100 = (z*4*5)/100

Therefore 

10x = 15y = 20z = k 

Therefore 

x : y : z = 1/10 : 1/15 : 1/20

Answer 2

Answer:

6 : 4 : 3

Step-by-step explanation:

Let the amount invested for son A, B and C are x, y and z,

Now, simple interest formula,

$I=\frac{P\times r\times t}{100}$

Where,

P = principal amount,

r = annual rate,

t = time in years,

According to the question,

Interest for A = interest for B = Interest for C,

Time for A = 2 years, for B = 3 years, for C = 4 years,

Percentage of interest rate, r = 5%

$\implies \frac{x\times 5\times 2}{100}=\frac{y\times 5\times 3}{100}=\fracz\times 5\times 4}{100}$

$10x = 15y = 20z$

If 10x = 15y ⇒ x : y = 3 : 2

If 15y = 20z ⇒ y : z = 4 : 3

⇒ x : y : z = 6 : 4 : 3

Hence, the ratio of the amounts invested among A, B and C will be 6 : 4 : 3.