Question

a man invests an amount of Rs.20000 in the name of his 3 sins A,B,C in such a way that they get same interest after 3,4,5 years respectat the rate of simple interest of 15% , find the share of B​

Answer 1

Given : a man invests an amount of Rs.20000 in the name of his 3 sons A,B,C in such a way that they get same interest after 3,4,5 years respectively  the rate of simple interest of 15% ,

To find :  the share of B​

Solution:

Amount of A  =   100x

Amount of B  =  100y

Amount of  C = 20000 - 100x-100y

interest of A = 100x   * 15 * 3 /100  =45x

interest of B = 100y  * 15 * 4 /100  = 60y

interest of C = (20000 - 100x-100y)  * 15 * 5 /100

=15000 - 75x - 75y

45x   = 60y  =15000 - 75x - 75y

=> 3x  = 4y = 1000 -  5x  -  5y

4y =1000 -   5x  - 5y

=>  9y =  000 -   5x

=>  9y = 2000 -  5(4y /3)

=>27y  = 3000 - 20y

=> 47y =3000

=> y =  3000/47

=> 100y = 100 * 3000/47  = 6382.98

Share of B =   6382.98  Rs

6383 Rs Approx

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Answer 2

Given :- a man invests an amount of Rs.20000 in the name of his 3 sons A,B,C in such a way that they get same interest after 3,4,5 years at the rate of simple interest of 15% , find the share of B ?

Answer :-

we know that, when interest is same in different years , then, ratio of share is equal to :-

• 1/R1*T1 : 1/R2*T2 : 1/R3*T3

here we have,

• R1 = R2 = R3 = 15%
• T1 = 3 years , T2 = 4 years , T3 = 5 years .

so,

→ A : B : C = 1/R1*T1 : 1/R2*T2 : 1/R3*T3

→ A : B : C = 1/3*15 : 1/4*15 : 1/5*15

→ A : B : C = 1/3 : 1/4 : 1/5

→ A : B : C = (20 : 15 : 12)/60

→ A : B : C = 20 : 15 : 12

then,

→ Share of B = (15/20 + 15 + 12) * 20000

→ Share of B = 15 * 20000 / 47

→ Share of B = Rs.6382.97 ≈ Rs.6383 (Ans.)

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