Math, asked by anindita197912, 2 months ago

A man invests an amount partly in two parts. In first one he invests at 10% per annum in simple interest and another at 10% per annum in compound interest. If he gets a total of ₹321. Find the amount invested in compound interest. both for simple interest and compound interest time will be of 2 years.​

Answers

Answered by hasinithirukovaluri
2

Answer:

Now, Rs. 16 is the S.I. on S.I. for 1 year.

∴ Rs. 10 is S.I. on Rs. 100

∴ Rs. 16 is S.I. on (  

10

100

×16)= Rs. 160

∴ S.I. on principal for 1 year at 10% is Rs. 160.

∴ Principal =(  

10×1

100×160

)= Rs.1600.

Amount for 2 years compounded half yearly

=Rs.[1600×(1+  

100

5

)  

4

]=Rs.1944.81

∴ C.I.Rs(1944.81−1600)=Rs.344.81

S.I.=Rs.(  

100

1600×10×2

)=Rs.320

∴(C.I.)−(S.I.)=Rs.(344.81−320)=Rs.24.81

Step-by-step explanation:

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