Question

A man is 10 times older than his grandson. He is also 54 years older than him.find their percent age.

Answer 1

Answer:

Let the present age of grandson be x year and Same of grandfather is y year.

Now, according to given conditions

y=10x

y=54+x

compare both equation, we get

10x= x+54

9x=54

x=6 years

and y= x+54

y=60 year.

Therefore, present age of grandson is 6 years and that of grandfather is 60 years.

hope it helps you!!

Answer 2

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The grandfather and his granddaughter’s present age are 60 years and 6 years respectively.

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Granddaughter’s age is 10 times lesser than the grandfather and the grandfather’s age is 54 more than his granddaughter.

Let us assume that the age of granddaughter and grandfather be x and y respectively

The equation representing the ages of grandfather and granddaughter are

$</p><p>\begin{gathered}\begin{array} { l } { y = 10 \times x \ldots . ( 1 ) } \\\\ { y = x + 54 \ldots . ( 2 ) } \end{array}\end{gathered} </p><p></p><p> </p><p>$

Substitute equation (1) in (2)

$\begin{gathered}\begin{array} { l } { 10 \mathtt { x } = \mathtt { x } + 54 } \\\\ { 10 \mathtt { x } - \mathtt { x } = 54 } \\\\ { 9 \mathtt { x } = 54 } \\\\ { \mathtt { x } = \frac { 54 } { 9 } = 6 } \end{array}\end{gathered} </p><p></p><p>$

The granddaughter age is 6 years

The grandfather age is 10 x=

$</p><p> \tt= 10 \times 6 = 60 \text { years }$

Thus, the present ages of grandfather and his granddaughter are 60 years and 6 years respectively.