Question

A man is 20 years elder to his son. After 10 years his age becomes twice the age of his son. Find their present age.

Answer 1

Yo!
Your Answer.

Let there age of the son be = x
So, Age of father = x + 20

AFTER 10 YEARS.

son's age = x + 10
father's age = x + 20 + 10 = x + 30

A/Q
2(x+10) = x + 30

2x + 20 = x + 30

2x - x = 30 - 20

x = 10

So,
Present age of son = 10 years
Present age of father = 10 + 20 = 30 years

$\bold{\underline{\underline{\boxed{Age\: of\:Son\:=\:10\: years }}}}$

$\bold{\underline{\underline{\boxed{Age \: of \: Father\:=\:30\: years }}}}$

VERIFICATION

2(10 + 10) = 10 + 30

40 = 40

HOPE IT HELPS.
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Answer 2

let the age of son be = X
so, his father's age will be = X + 20
their ages after ten years = X + 10 ( son's age )
.......................................X + 20 + 10. ( father's age )
•••now, we have an equation
...............
= ( X + 10 )2 = ( X + 20 ) + 10
= 2x + 20 = X + 30
= 2x - X = 30 - 20
....X = 10
so, the age of son = 10
and age of his father = X+ 20 = 10 + 20 = 30