Question

a man is 24 years older than his son after two years his age will be three times of his son the present age of son and father is ​

Answer 1

Answer:

let,

the present age of son is x

then after three years the age is 3x

then atq

=x+24=3x

=x-3x=-24

=-2x=-24

=x=-2/-24

=x=12

so,the present age of son is 12

and father is 3x=(3×12)=36

Answer 2

Answer:

Man age =34 years old and Son age is 10 years old

Step-by-step explanation:

Let the present age of son be taken as 'y' and the man as (y+24)

After 2 years the son age will be (y+2) and man age will be (y+24)+2

According to the question:-

After 2 years = Man will be thrice the age of his son

=> (y+24)+2= 3(y+2)

=> y+26= 3y+6

=> 3y-y= 26-6

=> 2y=20

=> y= 20/2

=> y= 10

•son age is 10 years old

Value of (y+24)

=> 10+24= 34

•father's age is 34 years old