Question

a man is 24 years older than his son. after two years his age will be two times the age of his son find their ages​

Answer 1

Answer:

The age of his son is 26

and the age of the man will be 52

Answer 2

Given :

• A man's age is 24 years older than his son.

• After two years his age will be two times the age of his son.

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To find :

• The original age of the man and the son.

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Assumption :

• Let the age of the son be x.

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Solution :

Following Criteria 1 -

A man's age is 24 years older than his son.

$\tt\:Man's~age~=~Son's~age~+~24$

$\tt\implies\:Man's~age~=~x~+~24$

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Following Criteria 2 -

After two years :

• Man's age = x + 24 + 2 = ( x+26 ) yrs

• Son's age = ( x+2 ) yes

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Now according to the question :

After two years age of man will be two times the age of his son.

$\tt\:Man's~age~=~2 \times Son's~age~$

$\tt\implies\:(x+26)~=~2 \times (x+2)~$

$\tt\implies\:(x+26)~=~2x+4~$

$\tt\:oR\:2x+4~=~x+26$

Transposing +x to LHS it becomes -x

$\tt\implies\:2x-x+4~=~26$

$\tt\implies\:x+4~=~26$

Transposing +4 to RHS it becomes -4

$\tt\implies\:x=~26-4$

$\small{\underline{\boxed{\mathrm{\implies\:x=22~yrs}}}}$

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Therefore plugging the values :

• Man's age = ( x+24 ) = 22 + 24 = 46yrs

• Son's age = x = 22yrs

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Henceforth :

⠀‎ ⠀⠀ ⠀⠀‎ ⠀⠀❒ The age of the man = $\large{\mathfrak\red{46~yrs}}$

⠀‎ ⠀⠀ ⠀⠀‎ ⠀⠀❒‎ The age of the son = $\large{\mathfrak\red{22~yrs}}$

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