Question

A man is 24 years older than his son. in 2 years, his age will be twice the age of his son. FIND THEIR PRESENT AGES.

Answer 1

Answer:Let the present age of the son be 'x'.

So, age of the man = x + 24

After two years, age of son will be = x + 2

and age of the man will be = (x + 24) + 2 = x + 26

Now, according to the question,

x + 26 = 2 (x +2)

x + 26 = 2x + 4

x = 22.

Hence, the present age of the son is 22 years.

Answer 2

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Answer:

x = 22

Their present ages are 22