A man is 24 years older than his son. in 2 years his age will be twice the age of his son. what is the present age of his son
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Let the age of son be x
Then age of father is x+24.
After 2 years,
Age of son = x+2
Age of father = x+24+2
= x+26
Now,
x+26 = 2(x+2)
x+26 = 2x+4
2x-x = 26-4
x = 22
Thus, age of the son is 22 years.
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Let the present age of his son be x years
So, His present age will be ( x + 24 ) years
According to the given information, after 2 years,
( x + 24 + 2 ) = 2( x + 2 )
=> x + 26 = 2x + 4
=> 26 - 4 = 2x - x
=> 22 = x
Hence, Present age of son = x = 22 years
His present age = ( x + 24 ) = ( 22 + 24 ) = 46 years
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