a man is 24 years older than his son.in 4 years his age will be twice the age of his son. find their present ages
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Answered by
7
let the age of son=X
then age of man =X+24
according to question
2(4+X)=(4+X+24)
8+2x=28+X
X=20
son age=20
man age =20+24=44
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then age of man =X+24
according to question
2(4+X)=(4+X+24)
8+2x=28+X
X=20
son age=20
man age =20+24=44
Mark me as BRAINLIEST IF YOU SATISFIED BY MY answer
best regards
Answered by
1
Answer:
The present age of man is 44 years and his son is 20 years.
Step-by-step explanation:
Let thye present age of the man be 'x' years and his son be 'y' years,
A man is 24 yrs older than his son.
∴ x = y + 24 → 1
In 4 yrs, his age will be twice the age of his son.
∴ x + 4 = 2(y + 4)
y + 24 + 4 = 2y + 8 (From 1)
y + 28 = 2y + 8
y - 2y = 8 - 28
-y = -20
∴ y = 20
x = y + 24
= 20 + 24
∴ x = 44.
∴The present age of man is 44 years and the present age of his son is 20 years.
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