Question

A man is 24 years older than his son. In two years, his age will be thrice the age of his son. The present age of his son is?

Answer 1

Answer:

The present ages of Son and father are 10 years and 34 years respectively.

Step-by-step explanation:

Given :

The Man is = 24 years older than his son

After 2 years = Man will be thrice the age of his son

To find :

Their present ages

Solution :

$\textsf{\underline{\underline{Let the present ages be -}}}$

• Son as y
• Man as (y + 24)

$\textsf{\underline{\underline{Ages after 2 years -}}}$

• Son = (y + 2)
• Man = (y + 24) + 2

$\textsf{\underline{\underline{According to the Question -}}}$

After 2 years = Man will be thrice the age of his son

⇒ (y + 24) + 2 = 3(y + 2)

⇒ y + 26 = 3y + 6

⇒ 3y - y = 26 - 6

⇒ 2y = 20

⇒ y = 20/2

⇒ y = 10

Son = 10 years old

$\rule{300}{1.5}$

★ Value of (y + 24)

⇒ 10 + 24

⇒ 34

Father = 34 years old

$\therefore$ The present ages of Son and father are 10 years and 34 years respectively.

Answer 2

ANSWER :-

The present age of son is 10 years.

EXPLANATION :-

Let the present age of son be 'x' years and present age of man be 'x + 24' years.

After 2 years,

Son's age = (x + 2) years

Man's age = (x + 24 + 2) = (x + 26) years

According to question,

$x + 26 = 3(x + 2) \\ x + 26 = 3x + 6 \\ x - 3x = - 26 + 6 \\ - 2x = - 20 \\ 2x = 20 \\ x = \frac{20}{2} \\ x = 10$

•°• The present age of son is 10 years.