A man is 24 years older than his son.In two years,his age will be twice the age of his son.What is the present age of his son.............
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suppose son's age is x
fathers age shall be x+24
Now after two years father's age shall be
x+24+2= 2x
x=26
fathers age shall be x+24
Now after two years father's age shall be
x+24+2= 2x
x=26
Answered by
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let the son's age be x years
then the age of man be x+24 years
after two years ,
the age of son be x+2 years
and the age of man be x+24+2 years
a/q..
2(x+2)=x+24+2
=> 2x+4=x+26
=>x =22
hence the age of son = 22years
and the age of man = 22+24 years
=46 years
then the age of man be x+24 years
after two years ,
the age of son be x+2 years
and the age of man be x+24+2 years
a/q..
2(x+2)=x+24+2
=> 2x+4=x+26
=>x =22
hence the age of son = 22years
and the age of man = 22+24 years
=46 years
Akb11:
thanks ramdina
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