Question

A man is 24 years older than his son. In two
years, his age will be twice the age of his son.
What is the present age of his son?​

Answer 1

Answer:

present age of son = 22

Step-by-step explanation:

let the age of son be x

ATQ

Man age = 24 + x

y = 24+ x

now second equation

y+2 = 2(x+2)

y = 2x + 4 - 2

y = 2x + 2

now equating the values

2x + 2 = 24 + x

x = 22

y = 46

Answer 2

Given

Man is 24 years older than his son.

Within two years the man would be twice the age of his son.

$\rule{300}{1}$

To find

The present age of the son.

$\rule{300}{1}$

Solution

Let's consider the son's present age to be ⇒ x

Man's present age would be ⇒ x + 24

To find the son's current age we will need to solve an equation. The equation we need to solve is ⇒ $(x+24) +2=2(x+2)$

Let's solve your equation step-by-step

$(x+24) +2=2(x+2)$

Step 1: Simplify both sides of the equation.

$x+24+2=2(x+2)$

(Distribute)

$x+24+2=(2)(x)+(2)(2)$

$x+24+2=2x+4$

(Combine Like Terms)

$(x)+(24+2)=2x+4$

$x+26=2x+4$

Step 2: Subtract 2x from both sides.

$x+26-2x=2x+4-2x$

$-x+26=4$

Step 3: Subtract 26 from both sides.

$-x+26-26=4-26$

$-x=-22$

Step 4: Divide both sides by -1.

$\frac{-x}{-1} =\frac{-22}{-1}$

$x=22$

∴ The current age of the son is 22 years.

$\rule{300}{1}$