A man is 24 years, older than his son. In two years, his age will be twice the age of his son. The present age of his son is
A.14 years
B.22 years
C.20 years
D.18 years
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let the son age be =x
the father age =x+24
after 2years his age will be twice the age of his son
A/q
2(x+4)+2=x+24+2
2x+6=x+26
2x-x=26-6
x=20
The present age of his son =20+2=22
the father age =x+24
after 2years his age will be twice the age of his son
A/q
2(x+4)+2=x+24+2
2x+6=x+26
2x-x=26-6
x=20
The present age of his son =20+2=22
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