Question

A man is 24 years older than his son. In two years his age will be twice the age of his son.The present age of his sonis

Answer 1

In Present

Let Age of Son=x years

Then,Age of Man=(x+24) years

After 2 years

Son Age=(x+2) years

Father Age=(x+24+2) years

Father Age is also 2×Son age after 2 years

MEANS

2(x+2)=(x+24+2)

2x+4=x+26

2x-x=26-4

x=22

X is age of Son =22 years

X+24 is age of Man=22+24=45 years

$\boxed{\mathtt{\huge{Son=22\:years}}}$

$\boxed{\mathtt{\huge{Man=46\:years}}}$

Answer 2

$\huge\bf\blue{\mid{\overline{\underline{Your\: Answer}}}\mid}$

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Son = 22 years

Father = 46 years

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step-by-step explanation:

Question:-

A man is 24 years older than his son. In two years his age will be twice the age of his son.The present age of his son is??

Solution:-

Let,

the ptesent age of son be x yrs.

then,

his father's present age will be (x+24) yrs.

Now,

after two years,

age of son = (x+2) years

age of father = (x +26) years

A.T.Q

x + 26 = 2(x+2)

=> 2x - x = 26 - 4

=> x = 22

Hence,

present age of

son is 22 years

and

Father is 46 years.


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