Question

a man is 24 yrs older than his daughter. In 4 yrs, his age will be twice the age of his daughter. Find the present age.

Answer 1

let x=daughter
so man=x+24

after 4 years
2x+4=x+24
2x-x=24-4
x=20

hope it is correct

Answer 2

$\bf{\underline{ ANSWER}}$

Let the daughter's age be x years

Man's age = x + 24 years

After four years,

Daughter's age = x + 4

Man's age = x + 24 + 4 = x + 28 years

$\bf{\underline{ A.T.Q.}}$

$\bf{\underline{ THE \: EQUATION \: FORMED}}$

=> x + 28 = 2 ( x + 4 )

=> x + 28 = 2x + 8

=> 2x - x = 28 - 8

=> x = 20

$\bf{\underline{ ANS}}$

$\bf{\underline{\huge{ Daughter's \: present \: age \: = \: 20 \:years}}}$

$\bf{\underline{\huge{ Man's \: present \: age \: = \: 20 \: + \: 24 \: = \:44 \: years}}}$

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