A MAN IS 26 YEARS OLDER THAN HIS SON. HE IS ALSO 8 YEARS OLD THAN THREE TIMES HIS SON'S AGE. FIND THE SON'S AGE.
Answers
Answer:
Let the age of the Son be ‘x’ years and the age of the father be ‘y’ years.
Now, consider the 1st case:
the man is 26 years older than his son, means, the age of the man is x+26=y…(1)
Now, consider the 2nd case:
the man is 8 years older than 3 times his son’s age is nothing but, 3x+8=y…(2)
Now we have got 2 variables, and 2 equations as well, so this makes it really easy to solve the problem.
x+26=3x+8
=> 26–8=3x-x
=> 18=2x
=> x=9
Hence, the age of the son is 9 years and that of his father is 9+26=35 years (equation 1).
thankyou...
Given : A Man in 26 year older than his son, Man is also 8 Years old than 3 times his son's age
To find : The Son's Age
Solution:
Let say Son age = S Years
Man in 26 year older than his son
=> Man' age = S + 26 Years
Man is also 8 Years old than 3 times his son's age
=< Man's age = 3S + 8
Equating Man's age
=> 3S + 8 =S + 26
=> 2S = 18
=> S = 9
Son's Age = 9 Years
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