Question

a man is 26 years older than his son in five years their ages will total 70 what are their present age​

Answer 1

Answer:

MAN AGE IS 26 YEARS OLDER THAN HIS SON. IN 5 YEARS THEIR AGE WILL TOTAL 70. WHAT ARE THEIR PRESENT AGE?

Answer by Fombitz(32378) (Show Source): You can put this solution on YOUR website!

M=S%2B26

In 5 years,

%28S%2B5%29%2B%28M%2B5%29=70

S%2BM%2B10=70

S%2BM=60

Substituting,

S%2B26%2BS=60

2S=34

S=17

Then,

M=17%2B26

M=43

PLS LIKE AND FOLLOW

Answer 2

$\huge\underline\bold{ \sf \: GiveN :-}$

• A man is 26 years older than his son.
• After 5 years the sum of their ages will be 70.

$\huge\underline\bold{ \sf \: To \: FinD :-}$

• Their present ages.

$\huge\underline\bold{ \sf \: SolutioN:-}$

${\sf \: Let,}$

the present age of son be x years . Then,

the present age of father = (x + 26) years.

${\sf \: after \: 5 \: years \: the \: age \: of \: }$

• Father = (x + 26) + 5 = x + 31
• Son =x + 5

A/q

After 5 years the sum of their ages will be 70.

${\sf \ \implies \: (x+ 31) + (x + 5) = 70 }$

${\sf \ \implies \:x + x + 31 + 5 = 70 }$

${\sf \ \implies \: 2x + 36 = 70 }$

${\sf \ \implies \: 2x = 70 - 36 }$

${\sf \ \implies \: 2x = 34 }$

${\sf \ \implies \: x = \frac{34}{2} }$

${\sf \ \implies \:x = 17 }$

${ \boxed{∵x = 17}}$

By putting the value of x

• present age of father = (x + 26) years

= ( 17 + 26 ) years

= 43 years

• the present age of son = x years

= 17 years

Therefore , the present age of father and his son is 43 years and 17 years respectively.