Question

A man is 27 years older than his son, and in 10 years from now he will be twice as old as his son. How old each is now?

Answer 1

let son's present age is x and father's age is y

a/c to question ,

y=x+27-----------(1)

again ,
y + 10 =2 (x + 10)
y + 10 = 2x +20
y -2 x = 10 -------(2)

solve equation (1) and (2)
x + 27 -2x =10
x =17
and y =17+ 27=44

hence ,
father's age =44 years
son's age =17 years