Math, asked by Msimna777, 1 year ago

A man is 27 years older than his son, and in 10 years from now he will be twice as old as his son. how old is each now?

Answers

Answered by uashenoy05
3
let the son's age be x
man's age 27x
after 10years ,
so add ten to both the ages
sons age 10+x
mans age27x+10
it is said that the man will be twice as old as his son .so
man age=2*sons age
27x+10=2*(10+x)
27x+10=20+2x
25x=10
x=10/25
x=2/5yrs=sons age
fathers age =27x
=27*2/5
fathers age =10.8yrs
i k ow this sounds wierd but i feel this is the correct answer.
if it helped pls mark my answer as brainliest
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