A man is 28.5 away from a tower . His eye level above the ground is 1.5 m. The angle of elevation of the tower from his eye is 45degree then the hight of tower is
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Answer:
h of the eye level abive the ground = x
distance b/w tiwer and man=28.5
angle of elevation= 45
H of the tower =??
Explanation:
tangent Q PERPENDICULAR /BASE
h of tower =28.5 +1.5
=30 ANSWER
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