Question

A man is 28 years old than his son . After10yearhe wil be thrice as old as son

Answer 1

Answer:

let the present age of son be X,

then present age of Man = x + 28... (i)

10 years hence,

age of son = x + 10

age of Man = 3 ( x + 10) = 3x + 30.... (ii)

now, the difference between their ages will remain constant,

so, (X + 28) - X = (3X + 30) - (X + 10)

28 = 3X - X + 30 - 10

28 = 2X + 20

28 - 20 = 2X

8 = 2X

X = 8/2 = 4 years

And age of Man = X + 28 = 4 + 28 = 32 years

Hence, the son is 4 years old and his father is 32 years old.