Question

a man is 28 years older than his son. After 10 years,he will be thrice as old as his son. find the present age.​

Answer 1

Answer:

The present age of the man is 32 years and his son's is 4 years.

Step-by-step explanation:

Let the man's age be 'x' and

     his son's age be 'y'.

Given the man is 28 years older than his son,

                 x=28+y→1

FUTURE:

After 10 years, he'll be thrice the old as his son.

 ∴x+10=3(y+10)

  x+10=3y+30

   x-3y=30-10

   x-3y=20

Substituing this in 1, we get:

28+y-3y=20

       -2y=20-28

       -2y=-8

           y=-8÷-2

        ⇒y=4.

Substituting this in 1, we get:

         x=28+y

           =28+4

        ∴x=32.

∴The present age of the man is 32 years and his son's is 4 years.

HOPE IT HELPS. MARK ME AS BRAINLIEST

Answer 2

Answer:

Age of son=x

Age of father=28+x

After 10 years

Age of son=x+10

Age of father=x+38

3(x+10)=x+38

3x+30=x+38

2x=8

x=4

Age of son=4

Age o father=4+28

=32