Question

A man is 28 years older than his son . After 10 years , he will be thrice as old as his son . Find their present age​

Answer 1

Answer:

Let the man's age be 'x' and  his son's age be 'y'.

Given the man is 28 years older than his son,   x=28+y→1

FUTURE:

After 10 years, he'll be thrice the old as his son.

∴x+10=3(y+10)

  x+10=3y+30

   x-3y=30-10

   x-3y=20

Substituting this in 1, we get:

28+y-3y=20

       -2y=20-28

       -2y=-8

           y=-8÷-2

        ⇒y=4.

Substituting this in 1, we get:

         x=28+y

           =28+4

        ∴x=32.

∴The present age of the man is 32 years and his son's is 4 years.

Hope it helps you.

Answer 2

Answer:

Let present age of son = x years

So, present age of father = x + 28 years,

After 10 years,

Age of son = x + 10 years

and age of father = x + 28 + 10 = x + 38 years,

Given that, after 10 years, age of father will be thrice as old as his son

=> x + 38 = 3(x + 10)

=> x + 38 = 3x + 30

=> 38 = 3x + 30 - x

=> 38 = 2x + 30

=> 2x = 38 - 30

=> 2x = 8

=> x = 8/2

=> x = 4

So, present age of son = x = 4 years

and present age of father = x + 28 = 4 + 28 = 32 years,

Step-by-step explanation:

mark as branlist answer