Question

A MAN IS 28 YEARS OLDER THAN HIS SON.AFTER 10 YEARS,HE WILL BE THRICE AS OLD AS HIS SON.FIND THEIR PRESENT AGES

Answer 1

Hi there !!

Let the son's age be x years
man is 28 years older than son,
so,
man's age = x + 28 years

After 10 years
man's age = x + 28 + 10 = x + 38 years
son's age = x + 10 years

After 10 years , the man will be thrice as old as his son,

the following balanced equation will be formed

3(x + 10) = x + 38

3x + 30 = x + 38

3x - x = 38 - 30

2x = 8

$x = \frac{8}{2}$
x = 4

So,

son's age = x = 4 years
man's age = x + 28 = 4 + 28 = 32 years

Answer 2

Let the son be x years
and the man be y years
A.T.Q
y=28+x--->1
y+10= 3(x+10)
y+10=3x+30
y=3x+20
from eq. 1
28+x=3x+20
8=2x
x=4
Put x=4 in eq. 1
y=28+4
y=32
Therefore, age of father=32 years
and, age of son=4 years