a man is 28 years older than his son .after 10 years he will be thrice as old as his son.find their present age
Answers
Answered by
6
let the son's age be x
so age of man =x+28
according to the question
age of man after 10yrs=x+28+10 and age of son after 10 yrs =x+10
x+28+10=3(x+10)
=>x+38=3x+30
=>x-3x=30-38
=>-2x=-8
=>x=-8/-2=4
so present age of son is 4 Yrs
age of man=4+28=32 yrs
so age of man =x+28
according to the question
age of man after 10yrs=x+28+10 and age of son after 10 yrs =x+10
x+28+10=3(x+10)
=>x+38=3x+30
=>x-3x=30-38
=>-2x=-8
=>x=-8/-2=4
so present age of son is 4 Yrs
age of man=4+28=32 yrs
Answered by
3
let's assume that M denotes the age of the men and S denotes the age of his son
Now, according to the question
M=S+28
M-S=28 and
M+10=3(S+10)
M-3S=20
subtracting second equation from first one we get
2S=8
S=4
substituting in first equation
M=32
so the men is 32 years old and his son is 4 years old.
#Prashant24IITBHU
Now, according to the question
M=S+28
M-S=28 and
M+10=3(S+10)
M-3S=20
subtracting second equation from first one we get
2S=8
S=4
substituting in first equation
M=32
so the men is 32 years old and his son is 4 years old.
#Prashant24IITBHU
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